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1390416668171 is a prime number
BaseRepresentation
bin10100001110111011010…
…010101010011000001011
311220220220112021002121222
4110032323102222120023
5140240033131340141
62542425410352255
7202311551451056
oct24167322523013
94826815232558
101390416668171
11496743a63243
121a557b88b68b
13a1167345a1b
144b421949a9d
152627bb5914b
hex143bb4aa60b

1390416668171 has 2 divisors, whose sum is σ = 1390416668172. Its totient is φ = 1390416668170.

The previous prime is 1390416668161. The next prime is 1390416668189. The reversal of 1390416668171 is 1718666140931.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (1718666140931) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1390416668171 is a prime.

It is a super-2 number, since 2×13904166681712 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1390416668161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 695208334085 + 695208334086.

It is an arithmetic number, because the mean of its divisors is an integer number (695208334086).

Almost surely, 21390416668171 is an apocalyptic number.

1390416668171 is a deficient number, since it is larger than the sum of its proper divisors (1).

1390416668171 is an equidigital number, since it uses as much as digits as its factorization.

1390416668171 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1306368, while the sum is 53.

The spelling of 1390416668171 in words is "one trillion, three hundred ninety billion, four hundred sixteen million, six hundred sixty-eight thousand, one hundred seventy-one".