Base | Representation |
---|---|
bin | 1100101010010111101011… |
… | …1011110001001100111101 |
3 | 1211021221020201001121110101 |
4 | 3022211322323301030331 |
5 | 3311044330140312332 |
6 | 45335411400041101 |
7 | 2634556262112112 |
oct | 312457273611475 |
9 | 54257221047411 |
10 | 13922051494717 |
11 | 4488344137993 |
12 | 168a22aa63191 |
13 | 79cac7b56042 |
14 | 361b8bd54909 |
15 | 192227ab4ae7 |
hex | ca97aef133d |
13922051494717 has 2 divisors, whose sum is σ = 13922051494718. Its totient is φ = 13922051494716.
The previous prime is 13922051494643. The next prime is 13922051494807. The reversal of 13922051494717 is 71749415022931.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8015178169881 + 5906873324836 = 2831109^2 + 2430406^2 .
It is a cyclic number.
It is not a de Polignac number, because 13922051494717 - 211 = 13922051492669 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13922051491717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6961025747358 + 6961025747359.
It is an arithmetic number, because the mean of its divisors is an integer number (6961025747359).
Almost surely, 213922051494717 is an apocalyptic number.
It is an amenable number.
13922051494717 is a deficient number, since it is larger than the sum of its proper divisors (1).
13922051494717 is an equidigital number, since it uses as much as digits as its factorization.
13922051494717 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3810240, while the sum is 55.
The spelling of 13922051494717 in words is "thirteen trillion, nine hundred twenty-two billion, fifty-one million, four hundred ninety-four thousand, seven hundred seventeen".
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