Base | Representation |
---|---|
bin | 11001111011101010… |
… | …01100110111100111 |
3 | 1022221021012000011021 |
4 | 30331311030313213 |
5 | 212003044232112 |
6 | 10221254152011 |
7 | 1002002146441 |
oct | 147565146747 |
9 | 38837160137 |
10 | 13922258407 |
11 | 59a482a892 |
12 | 2846652607 |
13 | 140b48c735 |
14 | 96103b491 |
15 | 5673c8907 |
hex | 33dd4cde7 |
13922258407 has 2 divisors, whose sum is σ = 13922258408. Its totient is φ = 13922258406.
The previous prime is 13922258333. The next prime is 13922258411. The reversal of 13922258407 is 70485222931.
It is a strong prime.
It is an emirp because it is prime and its reverse (70485222931) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13922258407 - 219 = 13921734119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13922258107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6961129203 + 6961129204.
It is an arithmetic number, because the mean of its divisors is an integer number (6961129204).
Almost surely, 213922258407 is an apocalyptic number.
13922258407 is a deficient number, since it is larger than the sum of its proper divisors (1).
13922258407 is an equidigital number, since it uses as much as digits as its factorization.
13922258407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 43.
The spelling of 13922258407 in words is "thirteen billion, nine hundred twenty-two million, two hundred fifty-eight thousand, four hundred seven".
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