13939433 has 4 divisors (see below), whose sum is σ = 13947780. Its totient is φ = 13931088.

The previous prime is 13939411. The next prime is 13939463. The reversal of 13939433 is 33493931.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 33493931 = 223 ⋅150197.

It can be written as a sum of positive squares in 2 ways, for example, as 7246864 + 6692569 = 2692^2 + 2587^2 .

It is a cyclic number.

It is not a de Polignac number, because 13939433 - 2¹⁰ = 13938409 is a prime.

It is a super-2 number, since 2×13939433² = 388615584722978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13939393 and 13939402.

It is not an unprimeable number, because it can be changed into a prime (13939463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 710 + ... + 5327.

It is an arithmetic number, because the mean of its divisors is an integer number (3486945).

Almost surely, 2^13939433 is an apocalyptic number.

It is an amenable number.

13939433 is a deficient number, since it is larger than the sum of its proper divisors (8347).

13939433 is an equidigital number, since it uses as much as digits as its factorization.

13939433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8346.

The product of its digits is 26244, while the sum is 35.

The square root of 13939433 is about 3733.5550082997. Note that the first 3 decimals coincide. The cubic root of 13939433 is about 240.6661642737. Note that the first 3 decimals are identical.

The spelling of 13939433 in words is "thirteen million, nine hundred thirty-nine thousand, four hundred thirty-three".