Base | Representation |
---|---|
bin | 11001111101111001… |
… | …10000000101110111 |
3 | 1022222120110221020022 |
4 | 30332330300011313 |
5 | 212022344434103 |
6 | 10223204155355 |
7 | 1002320446214 |
oct | 147674600567 |
9 | 38876427208 |
10 | 13941014903 |
11 | 5a04380922 |
12 | 2850998b5b |
13 | 1412328b5a |
14 | 963720b0b |
15 | 568d81138 |
hex | 33ef30177 |
13941014903 has 2 divisors, whose sum is σ = 13941014904. Its totient is φ = 13941014902.
The previous prime is 13941014831. The next prime is 13941014939. The reversal of 13941014903 is 30941014931.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13941014903 - 212 = 13941010807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13941014963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6970507451 + 6970507452.
It is an arithmetic number, because the mean of its divisors is an integer number (6970507452).
Almost surely, 213941014903 is an apocalyptic number.
13941014903 is a deficient number, since it is larger than the sum of its proper divisors (1).
13941014903 is an equidigital number, since it uses as much as digits as its factorization.
13941014903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 35.
The spelling of 13941014903 in words is "thirteen billion, nine hundred forty-one million, fourteen thousand, nine hundred three".
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