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139425001 = 523266587
BaseRepresentation
bin10000100111101…
…11010011101001
3100201100112010221
420103313103221
5241143100001
621500210041
73312043612
oct1023672351
9321315127
10139425001
117177a081
123a839921
1322b68701
1414734c09
15c3911a1
hex84f74e9

139425001 has 4 divisors (see below), whose sum is σ = 139692112. Its totient is φ = 139157892.

The previous prime is 139424993. The next prime is 139425029. The reversal of 139425001 is 100524931.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100524931 = 137732687.

It is a cyclic number.

It is not a de Polignac number, because 139425001 - 23 = 139424993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (139425031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132771 + ... + 133816.

It is an arithmetic number, because the mean of its divisors is an integer number (34923028).

Almost surely, 2139425001 is an apocalyptic number.

It is an amenable number.

139425001 is a deficient number, since it is larger than the sum of its proper divisors (267111).

139425001 is an equidigital number, since it uses as much as digits as its factorization.

139425001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 267110.

The product of its (nonzero) digits is 1080, while the sum is 25.

The square root of 139425001 is about 11807.8364233250. The cubic root of 139425001 is about 518.5375588047.

Adding to 139425001 its reverse (100524931), we get a palindrome (239949932).

The spelling of 139425001 in words is "one hundred thirty-nine million, four hundred twenty-five thousand, one".

Divisors: 1 523 266587 139425001