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13942993663 is a prime number
BaseRepresentation
bin11001111110001000…
…10011001011111111
31022222201012110120201
430333010103023333
5212023401244123
610223314424331
71002343330204
oct147704231377
938881173521
1013942993663
115a05502565
1228515920a7
13141286c711
14963ab7cab
155691225ad
hex33f1132ff

13942993663 has 2 divisors, whose sum is σ = 13942993664. Its totient is φ = 13942993662.

The previous prime is 13942993621. The next prime is 13942993667. The reversal of 13942993663 is 36639924931.

It is a strong prime.

It is an emirp because it is prime and its reverse (36639924931) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13942993663 - 213 = 13942985471 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13942993667) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6971496831 + 6971496832.

It is an arithmetic number, because the mean of its divisors is an integer number (6971496832).

Almost surely, 213942993663 is an apocalyptic number.

13942993663 is a deficient number, since it is larger than the sum of its proper divisors (1).

13942993663 is an equidigital number, since it uses as much as digits as its factorization.

13942993663 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5668704, while the sum is 55.

The spelling of 13942993663 in words is "thirteen billion, nine hundred forty-two million, nine hundred ninety-three thousand, six hundred sixty-three".