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1394551435147 = 13107273187319
BaseRepresentation
bin10100010010110001101…
…111100010111110001011
311221022120200120000121121
4110102301233202332023
5140322020131411042
62544351553020111
7202516166421223
oct24226157427613
94838520500547
101394551435147
11498475a24932
121a6334554637
13a1675b618c0
144b6d4b41083
152641eb50367
hex144b1be2f8b

1394551435147 has 4 divisors (see below), whose sum is σ = 1501824622480. Its totient is φ = 1287278247816.

The previous prime is 1394551435127. The next prime is 1394551435213. The reversal of 1394551435147 is 7415341554931.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1394551435147 - 227 = 1394417217419 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1394551435094 and 1394551435103.

It is not an unprimeable number, because it can be changed into a prime (1394551435127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53636593647 + ... + 53636593672.

It is an arithmetic number, because the mean of its divisors is an integer number (375456155620).

Almost surely, 21394551435147 is an apocalyptic number.

1394551435147 is a deficient number, since it is larger than the sum of its proper divisors (107273187333).

1394551435147 is a wasteful number, since it uses less digits than its factorization.

1394551435147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 107273187332.

The product of its digits is 4536000, while the sum is 52.

The spelling of 1394551435147 in words is "one trillion, three hundred ninety-four billion, five hundred fifty-one million, four hundred thirty-five thousand, one hundred forty-seven".

Divisors: 1 13 107273187319 1394551435147