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13948785029161 is a prime number
BaseRepresentation
bin1100101011111011010001…
…1000000111000000101001
31211101111020210220212110201
43022332310120013000221
53312014102431413121
645355552224312201
72636523616314553
oct312766430070051
954344223825421
1013948785029161
114498712561004
12169344ba72661
137a249857a788
143631a66324d3
15192c8ea61e91
hexcafb4607029

13948785029161 has 2 divisors, whose sum is σ = 13948785029162. Its totient is φ = 13948785029160.

The previous prime is 13948785029159. The next prime is 13948785029197. The reversal of 13948785029161 is 16192058784931.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10796185920025 + 3152599109136 = 3285755^2 + 1775556^2 .

It is a cyclic number.

It is not a de Polignac number, because 13948785029161 - 21 = 13948785029159 is a prime.

Together with 13948785029159, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13948785029093 and 13948785029102.

It is not a weakly prime, because it can be changed into another prime (13948785029111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6974392514580 + 6974392514581.

It is an arithmetic number, because the mean of its divisors is an integer number (6974392514581).

It is a 1-persistent number, because it is pandigital, but 2⋅13948785029161 = 27897570058322 is not.

Almost surely, 213948785029161 is an apocalyptic number.

It is an amenable number.

13948785029161 is a deficient number, since it is larger than the sum of its proper divisors (1).

13948785029161 is an equidigital number, since it uses as much as digits as its factorization.

13948785029161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26127360, while the sum is 64.

The spelling of 13948785029161 in words is "thirteen trillion, nine hundred forty-eight billion, seven hundred eighty-five million, twenty-nine thousand, one hundred sixty-one".