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139521740493 = 346507246831
BaseRepresentation
bin1000000111110000100…
…1001100111011001101
3111100010111202210001010
42001330021030323031
54241220031143433
6144032335035433
713036323140502
oct2017411147315
9440114683033
10139521740493
1154197426753
122305966bb79
131020677c5c5
146a77cd54a9
153968c4ee63
hex207c24cecd

139521740493 has 4 divisors (see below), whose sum is σ = 186028987328. Its totient is φ = 93014493660.

The previous prime is 139521740483. The next prime is 139521740497. The reversal of 139521740493 is 394047125931.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 139521740493 - 212 = 139521736397 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (139521740497) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23253623413 + ... + 23253623418.

It is an arithmetic number, because the mean of its divisors is an integer number (46507246832).

Almost surely, 2139521740493 is an apocalyptic number.

It is an amenable number.

139521740493 is a deficient number, since it is larger than the sum of its proper divisors (46507246835).

139521740493 is an equidigital number, since it uses as much as digits as its factorization.

139521740493 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46507246834.

The product of its (nonzero) digits is 816480, while the sum is 48.

The spelling of 139521740493 in words is "one hundred thirty-nine billion, five hundred twenty-one million, seven hundred forty thousand, four hundred ninety-three".

Divisors: 1 3 46507246831 139521740493