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139535024677 is a prime number
BaseRepresentation
bin1000000111110011101…
…1111000001000100101
3111100011102202200111221
42001330323320020211
54241231431242202
6144033531500341
713036544066056
oct2017473701045
9440142680457
10139535024677
11541a397a314
1223061bb76b1
1310209450c79
146a7999272d
153969ec6037
hex207cef8225

139535024677 has 2 divisors, whose sum is σ = 139535024678. Its totient is φ = 139535024676.

The previous prime is 139535024641. The next prime is 139535024701. The reversal of 139535024677 is 776420535931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89895630276 + 49639394401 = 299826^2 + 222799^2 .

It is a cyclic number.

It is not a de Polignac number, because 139535024677 - 215 = 139534991909 is a prime.

It is a super-2 number, since 2×1395350246772 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (139535024477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69767512338 + 69767512339.

It is an arithmetic number, because the mean of its divisors is an integer number (69767512339).

Almost surely, 2139535024677 is an apocalyptic number.

It is an amenable number.

139535024677 is a deficient number, since it is larger than the sum of its proper divisors (1).

139535024677 is an equidigital number, since it uses as much as digits as its factorization.

139535024677 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4762800, while the sum is 52.

The spelling of 139535024677 in words is "one hundred thirty-nine billion, five hundred thirty-five million, twenty-four thousand, six hundred seventy-seven".