139541121401 has 4 divisors (see below), whose sum is σ = 152226677904. Its totient is φ = 126855564900.

The previous prime is 139541121367. The next prime is 139541121413. The reversal of 139541121401 is 104121145931.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 139541121401 - 2³⁰ = 138467379577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (139541121451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6342778235 + ... + 6342778256.

It is an arithmetic number, because the mean of its divisors is an integer number (38056669476).

Almost surely, 2^139541121401 is an apocalyptic number.

139541121401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

139541121401 is a deficient number, since it is larger than the sum of its proper divisors (12685556503).

139541121401 is a wasteful number, since it uses less digits than its factorization.

139541121401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12685556502.

The product of its (nonzero) digits is 4320, while the sum is 32.

The spelling of 139541121401 in words is "one hundred thirty-nine billion, five hundred forty-one million, one hundred twenty-one thousand, four hundred one".