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13958112739691 is a prime number
BaseRepresentation
bin1100101100011110000001…
…0110100000000101101011
31211102101022212122122211002
43023013200112200011223
53312142203330132231
645404133553425215
72640304021460111
oct313074026400553
954371285578732
1013958112739691
1144a1669832a8a
12169521386b20b
137a3323bab713
1436380d391ab1
151931388c30cb
hexcb1e05a016b

13958112739691 has 2 divisors, whose sum is σ = 13958112739692. Its totient is φ = 13958112739690.

The previous prime is 13958112739661. The next prime is 13958112739693. The reversal of 13958112739691 is 19693721185931.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13958112739691 - 210 = 13958112738667 is a prime.

It is a super-2 number, since 2×139581127396912 (a number of 27 digits) contains 22 as substring.

Together with 13958112739693, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13958112739693) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6979056369845 + 6979056369846.

It is an arithmetic number, because the mean of its divisors is an integer number (6979056369846).

Almost surely, 213958112739691 is an apocalyptic number.

13958112739691 is a deficient number, since it is larger than the sum of its proper divisors (1).

13958112739691 is an equidigital number, since it uses as much as digits as its factorization.

13958112739691 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 22044960, while the sum is 65.

The spelling of 13958112739691 in words is "thirteen trillion, nine hundred fifty-eight billion, one hundred twelve million, seven hundred thirty-nine thousand, six hundred ninety-one".