Base | Representation |
---|---|
bin | 11010000000101100… |
… | …01010000000101001 |
3 | 1100001012120122201112 |
4 | 31000112022000221 |
5 | 212044344430011 |
6 | 10225402400105 |
7 | 1003023611462 |
oct | 150026120051 |
9 | 40035518645 |
10 | 13964451881 |
11 | 5a16629426 |
12 | 2858800035 |
13 | 14171437a3 |
14 | 9668a1d69 |
15 | 56ae6058b |
hex | 34058a029 |
13964451881 has 4 divisors (see below), whose sum is σ = 13964709264. Its totient is φ = 13964194500.
The previous prime is 13964451877. The next prime is 13964451883. The reversal of 13964451881 is 18815446931.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13964451881 - 22 = 13964451877 is a prime.
It is a super-2 number, since 2×139644518812 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13964451883) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12095 + ... + 167556.
It is an arithmetic number, because the mean of its divisors is an integer number (3491177316).
Almost surely, 213964451881 is an apocalyptic number.
It is an amenable number.
13964451881 is a deficient number, since it is larger than the sum of its proper divisors (257383).
13964451881 is an equidigital number, since it uses as much as digits as its factorization.
13964451881 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 257382.
The product of its digits is 829440, while the sum is 50.
The spelling of 13964451881 in words is "thirteen billion, nine hundred sixty-four million, four hundred fifty-one thousand, eight hundred eighty-one".
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