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1397214084545 = 5279442816909
BaseRepresentation
bin10100010101010000011…
…100101111110111000001
311221120110020210121220222
4110111100130233313001
5140342443301201140
62545512110512425
7202642160522366
oct24252034576701
94846406717828
101397214084545
11499611a1a824
121a6958205715
13a19ab69b6a6
144b8a861046d
15265287a85b5
hex1455072fdc1

1397214084545 has 4 divisors (see below), whose sum is σ = 1676656901460. Its totient is φ = 1117771267632.

The previous prime is 1397214084499. The next prime is 1397214084577. The reversal of 1397214084545 is 5454804127931.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 491703878656 + 905510205889 = 701216^2 + 951583^2 .

It is a cyclic number.

It is not a de Polignac number, because 1397214084545 - 28 = 1397214084289 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139721408450 + ... + 139721408459.

It is an arithmetic number, because the mean of its divisors is an integer number (419164225365).

Almost surely, 21397214084545 is an apocalyptic number.

It is an amenable number.

1397214084545 is a deficient number, since it is larger than the sum of its proper divisors (279442816915).

1397214084545 is an equidigital number, since it uses as much as digits as its factorization.

1397214084545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 279442816914.

The product of its (nonzero) digits is 4838400, while the sum is 53.

The spelling of 1397214084545 in words is "one trillion, three hundred ninety-seven billion, two hundred fourteen million, eighty-four thousand, five hundred forty-five".

Divisors: 1 5 279442816909 1397214084545