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1397430559873 is a prime number
BaseRepresentation
bin10100010101011101010…
…110100010010010000001
311221121000100010201020201
4110111131112202102001
5140343414210403443
62545545402405201
7202650426525655
oct24253526422201
94847010121221
101397430559873
11499713135957
121a69b8800801
13a1a144a39ba
144b8c9280a65
152653c7b934d
hex1455d5a2481

1397430559873 has 2 divisors, whose sum is σ = 1397430559874. Its totient is φ = 1397430559872.

The previous prime is 1397430559823. The next prime is 1397430559927. The reversal of 1397430559873 is 3789550347931.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1347751499329 + 49679060544 = 1160927^2 + 222888^2 .

It is a cyclic number.

It is not a de Polignac number, because 1397430559873 - 233 = 1388840625281 is a prime.

It is a super-2 number, since 2×13974305598732 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1397430559823) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 698715279936 + 698715279937.

It is an arithmetic number, because the mean of its divisors is an integer number (698715279937).

Almost surely, 21397430559873 is an apocalyptic number.

It is an amenable number.

1397430559873 is a deficient number, since it is larger than the sum of its proper divisors (1).

1397430559873 is an equidigital number, since it uses as much as digits as its factorization.

1397430559873 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 85730400, while the sum is 64.

The spelling of 1397430559873 in words is "one trillion, three hundred ninety-seven billion, four hundred thirty million, five hundred fifty-nine thousand, eight hundred seventy-three".