Base | Representation |
---|---|
bin | 10100010110000001100… |
… | …111110010101010000101 |
3 | 11221122120202010212211222 |
4 | 110112001213302222011 |
5 | 140401141000010143 |
6 | 2550130021010125 |
7 | 203001465652034 |
oct | 24260147625205 |
9 | 4848522125758 |
10 | 1398039063173 |
11 | 4999a5671445 |
12 | 1a6b48553945 |
13 | a1ab0588b1c |
14 | 4b945ddc71b |
15 | 26575e16768 |
hex | 145819f2a85 |
1398039063173 has 2 divisors, whose sum is σ = 1398039063174. Its totient is φ = 1398039063172.
The previous prime is 1398039063097. The next prime is 1398039063247. The reversal of 1398039063173 is 3713609308931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 867986628964 + 530052434209 = 931658^2 + 728047^2 .
It is a cyclic number.
It is not a de Polignac number, because 1398039063173 - 222 = 1398034868869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1398039083173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 699019531586 + 699019531587.
It is an arithmetic number, because the mean of its divisors is an integer number (699019531587).
Almost surely, 21398039063173 is an apocalyptic number.
It is an amenable number.
1398039063173 is a deficient number, since it is larger than the sum of its proper divisors (1).
1398039063173 is an equidigital number, since it uses as much as digits as its factorization.
1398039063173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2204496, while the sum is 53.
The spelling of 1398039063173 in words is "one trillion, three hundred ninety-eight billion, thirty-nine million, sixty-three thousand, one hundred seventy-three".
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