Base | Representation |
---|---|
bin | 1000001000110110011… |
… | …0100100001001100111 |
3 | 111100212220221010222211 |
4 | 2002031212210021213 |
5 | 4242320022303341 |
6 | 144121401104251 |
7 | 13046510630446 |
oct | 2021546441147 |
9 | 440786833884 |
10 | 139814650471 |
11 | 543277a8311 |
12 | 2311b788087 |
13 | 10252367212 |
14 | 6aa4b80d5d |
15 | 398480d181 |
hex | 208d9a4267 |
139814650471 has 2 divisors, whose sum is σ = 139814650472. Its totient is φ = 139814650470.
The previous prime is 139814650439. The next prime is 139814650477. The reversal of 139814650471 is 174056418931.
It is a strong prime.
It is an emirp because it is prime and its reverse (174056418931) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 139814650471 - 25 = 139814650439 is a prime.
It is a super-3 number, since 3×1398146504713 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (139814650477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69907325235 + 69907325236.
It is an arithmetic number, because the mean of its divisors is an integer number (69907325236).
Almost surely, 2139814650471 is an apocalyptic number.
139814650471 is a deficient number, since it is larger than the sum of its proper divisors (1).
139814650471 is an equidigital number, since it uses as much as digits as its factorization.
139814650471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 49.
The spelling of 139814650471 in words is "one hundred thirty-nine billion, eight hundred fourteen million, six hundred fifty thousand, four hundred seventy-one".
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