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13983000169 is a prime number
BaseRepresentation
bin11010000010111001…
…11010011001101001
31100002111111000012011
431001130322121221
5212114122001134
610231304115521
71003340353225
oct150134723151
940074430164
1013983000169
115a26047a96
122862a65ba1
13141ac391c8
1496912d785
1556c8c6264
hex34173a669

13983000169 has 2 divisors, whose sum is σ = 13983000170. Its totient is φ = 13983000168.

The previous prime is 13983000139. The next prime is 13983000179. The reversal of 13983000169 is 96100038931.

13983000169 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7505969769 + 6477030400 = 86637^2 + 80480^2 .

It is a cyclic number.

It is not a de Polignac number, because 13983000169 - 25 = 13983000137 is a prime.

It is a super-2 number, since 2×139830001692 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13983000139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6991500084 + 6991500085.

It is an arithmetic number, because the mean of its divisors is an integer number (6991500085).

Almost surely, 213983000169 is an apocalyptic number.

It is an amenable number.

13983000169 is a deficient number, since it is larger than the sum of its proper divisors (1).

13983000169 is an equidigital number, since it uses as much as digits as its factorization.

13983000169 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34992, while the sum is 40.

The spelling of 13983000169 in words is "thirteen billion, nine hundred eighty-three million, one hundred sixty-nine", and thus it is an aban number.