Base | Representation |
---|---|
bin | 1000001001000001101… |
… | …0100011100110011101 |
3 | 111101000012201022211011 |
4 | 2002100122203212131 |
5 | 4242414112143031 |
6 | 144130204255221 |
7 | 13050622655251 |
oct | 2022032434635 |
9 | 441005638734 |
10 | 139861834141 |
11 | 543513a5087 |
12 | 23133541511 |
13 | 1025c077753 |
14 | 6aab144261 |
15 | 3988a2d6b1 |
hex | 20906a399d |
139861834141 has 2 divisors, whose sum is σ = 139861834142. Its totient is φ = 139861834140.
The previous prime is 139861834111. The next prime is 139861834157. The reversal of 139861834141 is 141438168931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102749738116 + 37112096025 = 320546^2 + 192645^2 .
It is a cyclic number.
It is not a de Polignac number, because 139861834141 - 213 = 139861825949 is a prime.
It is a super-2 number, since 2×1398618341412 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (139861834111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69930917070 + 69930917071.
It is an arithmetic number, because the mean of its divisors is an integer number (69930917071).
Almost surely, 2139861834141 is an apocalyptic number.
It is an amenable number.
139861834141 is a deficient number, since it is larger than the sum of its proper divisors (1).
139861834141 is an equidigital number, since it uses as much as digits as its factorization.
139861834141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 497664, while the sum is 49.
The spelling of 139861834141 in words is "one hundred thirty-nine billion, eight hundred sixty-one million, eight hundred thirty-four thousand, one hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •