Base | Representation |
---|---|
bin | 101001101100111… |
… | …0101010110011101 |
3 | 10121111222211202012 |
4 | 1103121311112131 |
5 | 10331203443203 |
6 | 350503241005 |
7 | 46450456412 |
oct | 12331652635 |
9 | 3544884665 |
10 | 1399281053 |
11 | 658948625 |
12 | 330749165 |
13 | 193b89471 |
14 | d3ba6109 |
15 | 82ca1bd8 |
hex | 5367559d |
1399281053 has 2 divisors, whose sum is σ = 1399281054. Its totient is φ = 1399281052.
The previous prime is 1399281041. The next prime is 1399281071. The reversal of 1399281053 is 3501829931.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1397787769 + 1493284 = 37387^2 + 1222^2 .
It is a cyclic number.
It is not a de Polignac number, because 1399281053 - 28 = 1399280797 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1399281053.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1399281253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 699640526 + 699640527.
It is an arithmetic number, because the mean of its divisors is an integer number (699640527).
Almost surely, 21399281053 is an apocalyptic number.
It is an amenable number.
1399281053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1399281053 is an equidigital number, since it uses as much as digits as its factorization.
1399281053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 41.
The square root of 1399281053 is about 37406.9653005961. The cubic root of 1399281053 is about 1118.4974145165.
The spelling of 1399281053 in words is "one billion, three hundred ninety-nine million, two hundred eighty-one thousand, fifty-three".
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