14000000000041 has 16 divisors (see below), whose sum is σ = 15561092865600. Its totient is φ = 12486974269120.

The previous prime is 14000000000011. The next prime is 14000000000081.

14000000000041 is nontrivially palindromic in base 10.

It is a cyclic number.

It is not a de Polignac number, because 14000000000041 - 2⁵ = 14000000000009 is a prime.

It is a super-2 number, since 2×14000000000041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13999999999937 and 14000000000027.

It is not an unprimeable number, because it can be changed into a prime (14000000000011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 87544431 + ... + 87704203.

It is an arithmetic number, because the mean of its divisors is an integer number (972568304100).

Almost surely, 2^{14000000000041} is an apocalyptic number.

14000000000041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14000000000041 is a deficient number, since it is larger than the sum of its proper divisors (1561092865559).

14000000000041 is a wasteful number, since it uses less digits than its factorization.

14000000000041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 310136.

The product of its (nonzero) digits is 16, while the sum is 10.

It can be divided in two parts, 140000000000 and 41, that added together give a palindrome (140000000041).

The spelling of 14000000000041 in words is "fourteen trillion, forty-one", and thus it is an aban number.