14000000000081 has 2 divisors, whose sum is σ = 14000000000082. Its totient is φ = 14000000000080.

The previous prime is 14000000000011. The next prime is 14000000000113. The reversal of 14000000000081 is 18000000000041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13052258809681 + 947741190400 = 3612791^2 + 973520^2 .

It is an emirp because it is prime and its reverse (18000000000041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14000000000081 - 2⁴² = 9601953488977 is a prime.

It is a super-2 number, since 2×14000000000081² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13999999999975 and 14000000000065.

It is not a weakly prime, because it can be changed into another prime (14000000000011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000000000040 + 7000000000041.

It is an arithmetic number, because the mean of its divisors is an integer number (7000000000041).

Almost surely, 2^{14000000000081} is an apocalyptic number.

It is an amenable number.

14000000000081 is a deficient number, since it is larger than the sum of its proper divisors (1).

14000000000081 is an equidigital number, since it uses as much as digits as its factorization.

14000000000081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32, while the sum is 14.

The spelling of 14000000000081 in words is "fourteen trillion, eighty-one", and thus it is an aban number.