1400043434131 has 4 divisors (see below), whose sum is σ = 1429831592352. Its totient is φ = 1370255275912.

The previous prime is 1400043434087. The next prime is 1400043434143. The reversal of 1400043434131 is 1314343400041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1400043434131 - 2¹³ = 1400043425939 is a prime.

It is a super-2 number, since 2×1400043434131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1400043434131.

It is not an unprimeable number, because it can be changed into a prime (1400043434161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14894079040 + ... + 14894079133.

It is an arithmetic number, because the mean of its divisors is an integer number (357457898088).

Almost surely, 2^{1400043434131} is an apocalyptic number.

1400043434131 is a deficient number, since it is larger than the sum of its proper divisors (29788158221).

1400043434131 is an equidigital number, since it uses as much as digits as its factorization.

1400043434131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29788158220.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1400043434131 its reverse (1314343400041), we get a palindrome (2714386834172).

The spelling of 1400043434131 in words is "one trillion, four hundred billion, forty-three million, four hundred thirty-four thousand, one hundred thirty-one".