Base | Representation |
---|---|
bin | 10100010111111101010… |
… | …011111011001111100001 |
3 | 11221211221100221021220112 |
4 | 110113331103323033201 |
5 | 140414413220331431 |
6 | 2551111551021105 |
7 | 203104064410556 |
oct | 24277523731741 |
9 | 4854840837815 |
10 | 1400114230241 |
11 | 49a86aa89151 |
12 | 1a742750a795 |
13 | a205149082c |
14 | 4baa1862a2d |
15 | 266481c5c2b |
hex | 145fd4fb3e1 |
1400114230241 has 2 divisors, whose sum is σ = 1400114230242. Its totient is φ = 1400114230240.
The previous prime is 1400114230237. The next prime is 1400114230289. The reversal of 1400114230241 is 1420324110041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1203979507600 + 196134722641 = 1097260^2 + 442871^2 .
It is a cyclic number.
It is not a de Polignac number, because 1400114230241 - 22 = 1400114230237 is a prime.
It is not a weakly prime, because it can be changed into another prime (1400114260241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700057115120 + 700057115121.
It is an arithmetic number, because the mean of its divisors is an integer number (700057115121).
Almost surely, 21400114230241 is an apocalyptic number.
It is an amenable number.
1400114230241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400114230241 is an equidigital number, since it uses as much as digits as its factorization.
1400114230241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 1400114230241 its reverse (1420324110041), we get a palindrome (2820438340282).
The spelling of 1400114230241 in words is "one trillion, four hundred billion, one hundred fourteen million, two hundred thirty thousand, two hundred forty-one".
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