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140011444444444 = 2235002861111111
BaseRepresentation
bin11111110101011011110100…
…011010010001110100011100
3200100201222000021222112222221
4133311123310122101310130
5121322421414234210234
61213440211501115124
741330331054332236
oct3765336432216434
9610658007875887
10140011444444444
114068057a3307a1
12138531a5558aa4
13601803a73b111
142680839211256
15112c0440bceb4
hex7f56f4691d1c

140011444444444 has 6 divisors (see below), whose sum is σ = 245020027777784. Its totient is φ = 70005722222220.

The previous prime is 140011444444387. The next prime is 140011444444457. The reversal of 140011444444444 is 444444444110041.

It is a super-3 number, since 3×1400114444444443 (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 140011444444444.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17501430555552 + ... + 17501430555559.

Almost surely, 2140011444444444 is an apocalyptic number.

It is an amenable number.

140011444444444 is a deficient number, since it is larger than the sum of its proper divisors (105008583333340).

140011444444444 is a wasteful number, since it uses less digits than its factorization.

140011444444444 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35002861111115 (or 35002861111113 counting only the distinct ones).

The product of its (nonzero) digits is 1048576, while the sum is 43.

Adding to 140011444444444 its reverse (444444444110041), we get a palindrome (584455888554485).

The spelling of 140011444444444 in words is "one hundred forty trillion, eleven billion, four hundred forty-four million, four hundred forty-four thousand, four hundred forty-four".

Divisors: 1 2 4 35002861111111 70005722222222 140011444444444