Base | Representation |
---|---|
bin | 11111110101011100010101… |
… | …100010001011111001000111 |
3 | 200100202000110000200002220022 |
4 | 133311130111202023321013 |
5 | 121322424034020243242 |
6 | 1213440342552125355 |
7 | 41330350613022134 |
oct | 3765342542137107 |
9 | 610660400602808 |
10 | 140012000165447 |
11 | 40680834a96153 |
12 | 1385331b69685b |
13 | 60180c8902607 |
14 | 268088cd4d58b |
15 | 112c077c910d2 |
hex | 7f571588be47 |
140012000165447 has 2 divisors, whose sum is σ = 140012000165448. Its totient is φ = 140012000165446.
The previous prime is 140012000165369. The next prime is 140012000165489. The reversal of 140012000165447 is 744561000210041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140012000165447 - 212 = 140012000161351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140012000165347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006000082723 + 70006000082724.
It is an arithmetic number, because the mean of its divisors is an integer number (70006000082724).
Almost surely, 2140012000165447 is an apocalyptic number.
140012000165447 is a deficient number, since it is larger than the sum of its proper divisors (1).
140012000165447 is an equidigital number, since it uses as much as digits as its factorization.
140012000165447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26880, while the sum is 35.
Adding to 140012000165447 its reverse (744561000210041), we get a palindrome (884573000375488).
The spelling of 140012000165447 in words is "one hundred forty trillion, twelve billion, one hundred sixty-five thousand, four hundred forty-seven".
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