140012000410003 has 2 divisors, whose sum is σ = 140012000410004. Its totient is φ = 140012000410002.

The previous prime is 140012000409979. The next prime is 140012000410019. The reversal of 140012000410003 is 300014000210041.

It is an a-pointer prime, because the next prime (140012000410019) can be obtained adding 140012000410003 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140012000410003 - 2¹³ = 140012000401811 is a prime.

It is not a weakly prime, because it can be changed into another prime (140012000410043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006000205001 + 70006000205002.

It is an arithmetic number, because the mean of its divisors is an integer number (70006000205002).

Almost surely, 2^{140012000410003} is an apocalyptic number.

140012000410003 is a deficient number, since it is larger than the sum of its proper divisors (1).

140012000410003 is an equidigital number, since it uses as much as digits as its factorization.

140012000410003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 140012000410003 its reverse (300014000210041), we get a palindrome (440026000620044).

The spelling of 140012000410003 in words is "one hundred forty trillion, twelve billion, four hundred ten thousand, three".