14001201201511 has 2 divisors, whose sum is σ = 14001201201512. Its totient is φ = 14001201201510.

The previous prime is 14001201201349. The next prime is 14001201201523. The reversal of 14001201201511 is 11510210210041.

It is a strong prime.

It is an emirp because it is prime and its reverse (11510210210041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14001201201511 - 2¹¹ = 14001201199463 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14001201201311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000600600755 + 7000600600756.

It is an arithmetic number, because the mean of its divisors is an integer number (7000600600756).

Almost surely, 2^{14001201201511} is an apocalyptic number.

14001201201511 is a deficient number, since it is larger than the sum of its proper divisors (1).

14001201201511 is an equidigital number, since it uses as much as digits as its factorization.

14001201201511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 19.

Adding to 14001201201511 its reverse (11510210210041), we get a palindrome (25511411411552).

The spelling of 14001201201511 in words is "fourteen trillion, one billion, two hundred one million, two hundred one thousand, five hundred eleven".