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1400121102013 is a prime number
BaseRepresentation
bin10100010111111101101…
…110001000111010111101
311221211221211212102012121
4110113331232020322331
5140414422000231023
62551112354202541
7203104210001104
oct24277556107275
94854854772177
101400121102013
1149a873951aa7
121a7429883451
13a2052a2857a
144baa273103b
1526648ad1d5d
hex145fdb88ebd

1400121102013 has 2 divisors, whose sum is σ = 1400121102014. Its totient is φ = 1400121102012.

The previous prime is 1400121102001. The next prime is 1400121102067. The reversal of 1400121102013 is 3102011210041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 930804307524 + 469316794489 = 964782^2 + 685067^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1400121102013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1400121102113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700060551006 + 700060551007.

It is an arithmetic number, because the mean of its divisors is an integer number (700060551007).

Almost surely, 21400121102013 is an apocalyptic number.

It is an amenable number.

1400121102013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400121102013 is an equidigital number, since it uses as much as digits as its factorization.

1400121102013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1400121102013 its reverse (3102011210041), we get a palindrome (4502132312054).

The spelling of 1400121102013 in words is "one trillion, four hundred billion, one hundred twenty-one million, one hundred two thousand, thirteen".