1400121201131 has 2 divisors, whose sum is σ = 1400121201132. Its totient is φ = 1400121201130.

The previous prime is 1400121201079. The next prime is 1400121201191. The reversal of 1400121201131 is 1311021210041.

It is a weak prime.

It is an emirp because it is prime and its reverse (1311021210041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1400121201131 is a prime.

It is a super-2 number, since 2×1400121201131² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1400121201191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700060600565 + 700060600566.

It is an arithmetic number, because the mean of its divisors is an integer number (700060600566).

Almost surely, 2^{1400121201131} is an apocalyptic number.

1400121201131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400121201131 is an equidigital number, since it uses as much as digits as its factorization.

1400121201131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1400121201131 its reverse (1311021210041), we get a palindrome (2711142411172).

The spelling of 1400121201131 in words is "one trillion, four hundred billion, one hundred twenty-one million, two hundred one thousand, one hundred thirty-one".