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14001222400003 = 71448343988471
BaseRepresentation
bin1100101110111110100111…
…1000110011100000000011
31211120111121021002022022201
43023233221320303200003
53313344000413300003
645440023415214031
72643361225522006
oct313575170634003
954514537068281
1014001222400003
114508981040923
1216a1645077317
137a740428c067
1436593c94d53d
1519430d3b0b1d
hexcbbe9e33803

14001222400003 has 8 divisors (see below), whose sum is σ = 14201590208256. Its totient is φ = 13800942577800.

The previous prime is 14001222399821. The next prime is 14001222400021. The reversal of 14001222400003 is 30000422210041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14001222400003 - 217 = 14001222268931 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14001222400073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21675943 + ... + 22312528.

It is an arithmetic number, because the mean of its divisors is an integer number (1775198776032).

Almost surely, 214001222400003 is an apocalyptic number.

14001222400003 is a deficient number, since it is larger than the sum of its proper divisors (200367808253).

14001222400003 is an equidigital number, since it uses as much as digits as its factorization.

14001222400003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43993025.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 14001222400003 its reverse (30000422210041), we get a palindrome (44001644610044).

The spelling of 14001222400003 in words is "fourteen trillion, one billion, two hundred twenty-two million, four hundred thousand, three".

Divisors: 1 71 4483 318293 43988471 3123181441 197200315493 14001222400003