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140012224000471 is a prime number
BaseRepresentation
bin11111110101011100100010…
…111000000011000111010111
3200100202001000121212002211101
4133311130202320003013113
5121322430013321003341
61213440421105450531
741330356301420314
oct3765344270030727
9610661017762741
10140012224000471
114068093a378779
1213853382640a47
1360181330b3784
1426808b0977d0b
15112c08c757831
hex7f5722e031d7

140012224000471 has 2 divisors, whose sum is σ = 140012224000472. Its totient is φ = 140012224000470.

The previous prime is 140012224000423. The next prime is 140012224000507. The reversal of 140012224000471 is 174000422210041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140012224000471 - 215 = 140012223967703 is a prime.

It is a super-3 number, since 3×1400122240004713 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140012224400471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006112000235 + 70006112000236.

It is an arithmetic number, because the mean of its divisors is an integer number (70006112000236).

Almost surely, 2140012224000471 is an apocalyptic number.

140012224000471 is a deficient number, since it is larger than the sum of its proper divisors (1).

140012224000471 is an equidigital number, since it uses as much as digits as its factorization.

140012224000471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3584, while the sum is 28.

The spelling of 140012224000471 in words is "one hundred forty trillion, twelve billion, two hundred twenty-four million, four hundred seventy-one", and thus it is an aban number.