Base | Representation |
---|---|
bin | 1100101110111110100111… |
… | …1111010101011111100110 |
3 | 1211120111121101022021212210 |
4 | 3023233221333111133212 |
5 | 3313344001333041402 |
6 | 45440023520024250 |
7 | 2643361246212363 |
oct | 313575177253746 |
9 | 54514541267783 |
10 | 14001224112102 |
11 | 4508982000187 |
12 | 16a1645762086 |
13 | 7a740473b436 |
14 | 36593cc7746a |
15 | 19430d5ed06c |
hex | cbbe9fd57e6 |
14001224112102 has 8 divisors (see below), whose sum is σ = 28002448224216. Its totient is φ = 4667074704032.
The previous prime is 14001224112091. The next prime is 14001224112149. The reversal of 14001224112102 is 20121142210041.
It is a sphenic number, since it is the product of 3 distinct primes.
14001224112102 is an admirable number.
It is a super-3 number, since 3×140012241121023 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1166768676003 + ... + 1166768676014.
It is an arithmetic number, because the mean of its divisors is an integer number (3500306028027).
Almost surely, 214001224112102 is an apocalyptic number.
14001224112102 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14001224112102 is a wasteful number, since it uses less digits than its factorization.
14001224112102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2333537352022.
The product of its (nonzero) digits is 256, while the sum is 21.
Adding to 14001224112102 its reverse (20121142210041), we get a palindrome (34122366322143).
The spelling of 14001224112102 in words is "fourteen trillion, one billion, two hundred twenty-four million, one hundred twelve thousand, one hundred two".
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