140013003000401 has 2 divisors, whose sum is σ = 140013003000402. Its totient is φ = 140013003000400.

The previous prime is 140013003000341. The next prime is 140013003000419. The reversal of 140013003000401 is 104000300310041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85342491610000 + 54670511390401 = 9238100^2 + 7393951^2 .

It is a cyclic number.

It is not a de Polignac number, because 140013003000401 - 2²⁶ = 140012935891537 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 140013003000401.

It is not a weakly prime, because it can be changed into another prime (140013003000461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006501500200 + 70006501500201.

It is an arithmetic number, because the mean of its divisors is an integer number (70006501500201).

Almost surely, 2^{140013003000401} is an apocalyptic number.

It is an amenable number.

140013003000401 is a deficient number, since it is larger than the sum of its proper divisors (1).

140013003000401 is an equidigital number, since it uses as much as digits as its factorization.

140013003000401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 140013003000401 its reverse (104000300310041), we get a palindrome (244013303310442).

The spelling of 140013003000401 in words is "one hundred forty trillion, thirteen billion, three million, four hundred one", and thus it is an aban number.