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140013003342302 = 270006501671151
BaseRepresentation
bin11111110101011101010001…
…010101000000000111011110
3200100202010000221022202211122
4133311131101111000013132
5121322433112323423202
61213441030305450542
741330414513624036
oct3765352125000736
9610663027282748
10140013003342302
11406811aa289832
121385355b640a52
1360182286b279c
1426809462868c6
15112c0d5d9d9a2
hex7f57515401de

140013003342302 has 4 divisors (see below), whose sum is σ = 210019505013456. Its totient is φ = 70006501671150.

The previous prime is 140013003342293. The next prime is 140013003342307. The reversal of 140013003342302 is 203243300310041.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1400130033423022 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140013003342307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35003250835574 + ... + 35003250835577.

It is an arithmetic number, because the mean of its divisors is an integer number (52504876253364).

Almost surely, 2140013003342302 is an apocalyptic number.

140013003342302 is a deficient number, since it is larger than the sum of its proper divisors (70006501671154).

140013003342302 is an equidigital number, since it uses as much as digits as its factorization.

140013003342302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70006501671153.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 140013003342302 its reverse (203243300310041), we get a palindrome (343256303652343).

The spelling of 140013003342302 in words is "one hundred forty trillion, thirteen billion, three million, three hundred forty-two thousand, three hundred two".

Divisors: 1 2 70006501671151 140013003342302