Base | Representation |
---|---|
bin | 11111110101011101010001… |
… | …011000010001110110111011 |
3 | 200100202010000222221102022012 |
4 | 133311131101120101312323 |
5 | 121322433113033421103 |
6 | 1213441030340120135 |
7 | 41330414524132514 |
oct | 3765352130216673 |
9 | 610663028842265 |
10 | 140013004201403 |
11 | 406811aa816233 |
12 | 1385355b99604b |
13 | 6018228923828 |
14 | 268094642ba0b |
15 | 112c0d5ebd2d8 |
hex | 7f5751611dbb |
140013004201403 has 4 divisors (see below), whose sum is σ = 140013098331288. Its totient is φ = 140012910071520.
The previous prime is 140013004201387. The next prime is 140013004201489. The reversal of 140013004201403 is 304102400310041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140013004201403 - 24 = 140013004201387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140013004201703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44797358 + ... + 47820803.
It is an arithmetic number, because the mean of its divisors is an integer number (35003274582822).
Almost surely, 2140013004201403 is an apocalyptic number.
140013004201403 is a deficient number, since it is larger than the sum of its proper divisors (94129885).
140013004201403 is an equidigital number, since it uses as much as digits as its factorization.
140013004201403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94129884.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 140013004201403 its reverse (304102400310041), we get a palindrome (444115404511444).
The spelling of 140013004201403 in words is "one hundred forty trillion, thirteen billion, four million, two hundred one thousand, four hundred three".
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