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140013004201403 = 151172392618161
BaseRepresentation
bin11111110101011101010001…
…011000010001110110111011
3200100202010000222221102022012
4133311131101120101312323
5121322433113033421103
61213441030340120135
741330414524132514
oct3765352130216673
9610663028842265
10140013004201403
11406811aa816233
121385355b99604b
136018228923828
14268094642ba0b
15112c0d5ebd2d8
hex7f5751611dbb

140013004201403 has 4 divisors (see below), whose sum is σ = 140013098331288. Its totient is φ = 140012910071520.

The previous prime is 140013004201387. The next prime is 140013004201489. The reversal of 140013004201403 is 304102400310041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140013004201403 - 24 = 140013004201387 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140013004201703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44797358 + ... + 47820803.

It is an arithmetic number, because the mean of its divisors is an integer number (35003274582822).

Almost surely, 2140013004201403 is an apocalyptic number.

140013004201403 is a deficient number, since it is larger than the sum of its proper divisors (94129885).

140013004201403 is an equidigital number, since it uses as much as digits as its factorization.

140013004201403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 94129884.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 140013004201403 its reverse (304102400310041), we get a palindrome (444115404511444).

The spelling of 140013004201403 in words is "one hundred forty trillion, thirteen billion, four million, two hundred one thousand, four hundred three".

Divisors: 1 1511723 92618161 140013004201403