140013103331141 has 4 divisors (see below), whose sum is σ = 147382214032800. Its totient is φ = 132643992629484.

The previous prime is 140013103331041. The next prime is 140013103331149. The reversal of 140013103331141 is 141133301310041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140013103331141 - 2²⁶ = 140013036222277 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 140013103331141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140013103331149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3684555350801 + ... + 3684555350838.

It is an arithmetic number, because the mean of its divisors is an integer number (36845553508200).

Almost surely, 2^{140013103331141} is an apocalyptic number.

It is an amenable number.

140013103331141 is a deficient number, since it is larger than the sum of its proper divisors (7369110701659).

140013103331141 is an equidigital number, since it uses as much as digits as its factorization.

140013103331141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7369110701658.

The product of its (nonzero) digits is 1296, while the sum is 26.

Adding to 140013103331141 its reverse (141133301310041), we get a palindrome (281146404641182).

The spelling of 140013103331141 in words is "one hundred forty trillion, thirteen billion, one hundred three million, three hundred thirty-one thousand, one hundred forty-one".