14001311301 has 4 divisors (see below), whose sum is σ = 18668415072. Its totient is φ = 9334207532.

The previous prime is 14001311287. The next prime is 14001311321. The reversal of 14001311301 is 10311310041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10311310041 = 3 ⋅3437103347.

It is a cyclic number.

It is not a de Polignac number, because 14001311301 - 2²² = 13997116997 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14001311321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2333551881 + ... + 2333551886.

It is an arithmetic number, because the mean of its divisors is an integer number (4667103768).

Almost surely, 2^14001311301 is an apocalyptic number.

It is an amenable number.

14001311301 is a deficient number, since it is larger than the sum of its proper divisors (4667103771).

14001311301 is an equidigital number, since it uses as much as digits as its factorization.

14001311301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4667103770.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 14001311301 its reverse (10311310041), we get a palindrome (24312621342).

The spelling of 14001311301 in words is "fourteen billion, one million, three hundred eleven thousand, three hundred one".