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140013210433 is a prime number
BaseRepresentation
bin1000001001100101110…
…0000000101101000001
3111101101202120001001111
42002121130000231001
54243221340213213
6144153213003321
713054441436455
oct2023134005501
9441352501044
10140013210433
1154419897358
1223176183541
1310284538c15
146ac32aa665
153996e80a3d
hex2099700b41

140013210433 has 2 divisors, whose sum is σ = 140013210434. Its totient is φ = 140013210432.

The previous prime is 140013210409. The next prime is 140013210443. The reversal of 140013210433 is 334012310041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 139978494769 + 34715664 = 374137^2 + 5892^2 .

It is a cyclic number.

It is not a de Polignac number, because 140013210433 - 225 = 139979656001 is a prime.

It is not a weakly prime, because it can be changed into another prime (140013210443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006605216 + 70006605217.

It is an arithmetic number, because the mean of its divisors is an integer number (70006605217).

Almost surely, 2140013210433 is an apocalyptic number.

It is an amenable number.

140013210433 is a deficient number, since it is larger than the sum of its proper divisors (1).

140013210433 is an equidigital number, since it uses as much as digits as its factorization.

140013210433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 140013210433 its reverse (334012310041), we get a palindrome (474025520474).

The spelling of 140013210433 in words is "one hundred forty billion, thirteen million, two hundred ten thousand, four hundred thirty-three".