Base | Representation |
---|---|
bin | 10100010111111110011… |
… | …101111110010110110011 |
3 | 11221211222201110111100122 |
4 | 110113332131332112303 |
5 | 140414433203013101 |
6 | 2551113523040455 |
7 | 203104421405603 |
oct | 24277635762663 |
9 | 4854881414318 |
10 | 1400133641651 |
11 | 49a87aa37238 |
12 | 1a7431b1012b |
13 | a20554c9084 |
14 | 4baa4276c03 |
15 | 26649c5c51b |
hex | 145fe77e5b3 |
1400133641651 has 2 divisors, whose sum is σ = 1400133641652. Its totient is φ = 1400133641650.
The previous prime is 1400133641609. The next prime is 1400133641653. The reversal of 1400133641651 is 1561463310041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1400133641651 - 210 = 1400133640627 is a prime.
Together with 1400133641653, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1400133641653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700066820825 + 700066820826.
It is an arithmetic number, because the mean of its divisors is an integer number (700066820826).
Almost surely, 21400133641651 is an apocalyptic number.
1400133641651 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400133641651 is an equidigital number, since it uses as much as digits as its factorization.
1400133641651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 35.
Adding to 1400133641651 its reverse (1561463310041), we get a palindrome (2961596951692).
The spelling of 1400133641651 in words is "one trillion, four hundred billion, one hundred thirty-three million, six hundred forty-one thousand, six hundred fifty-one".
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