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1400133641651 is a prime number
BaseRepresentation
bin10100010111111110011…
…101111110010110110011
311221211222201110111100122
4110113332131332112303
5140414433203013101
62551113523040455
7203104421405603
oct24277635762663
94854881414318
101400133641651
1149a87aa37238
121a7431b1012b
13a20554c9084
144baa4276c03
1526649c5c51b
hex145fe77e5b3

1400133641651 has 2 divisors, whose sum is σ = 1400133641652. Its totient is φ = 1400133641650.

The previous prime is 1400133641609. The next prime is 1400133641653. The reversal of 1400133641651 is 1561463310041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1400133641651 - 210 = 1400133640627 is a prime.

Together with 1400133641653, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1400133641653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700066820825 + 700066820826.

It is an arithmetic number, because the mean of its divisors is an integer number (700066820826).

Almost surely, 21400133641651 is an apocalyptic number.

1400133641651 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400133641651 is an equidigital number, since it uses as much as digits as its factorization.

1400133641651 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 35.

Adding to 1400133641651 its reverse (1561463310041), we get a palindrome (2961596951692).

The spelling of 1400133641651 in words is "one trillion, four hundred billion, one hundred thirty-three million, six hundred forty-one thousand, six hundred fifty-one".