1400133645761 has 2 divisors, whose sum is σ = 1400133645762. Its totient is φ = 1400133645760.

The previous prime is 1400133645737. The next prime is 1400133645763. The reversal of 1400133645761 is 1675463310041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 838579747600 + 561553898161 = 915740^2 + 749369^2 .

It is an emirp because it is prime and its reverse (1675463310041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1400133645761 - 2³⁴ = 1382953776577 is a prime.

Together with 1400133645763, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1400133645763) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700066822880 + 700066822881.

It is an arithmetic number, because the mean of its divisors is an integer number (700066822881).

Almost surely, 2^{1400133645761} is an apocalyptic number.

It is an amenable number.

1400133645761 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400133645761 is an equidigital number, since it uses as much as digits as its factorization.

1400133645761 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 181440, while the sum is 41.

The spelling of 1400133645761 in words is "one trillion, four hundred billion, one hundred thirty-three million, six hundred forty-five thousand, seven hundred sixty-one".