1400141213431 has 4 divisors (see below), whose sum is σ = 1400177867200. Its totient is φ = 1400104559664.

The previous prime is 1400141213411. The next prime is 1400141213441. The reversal of 1400141213431 is 1343121410041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1400141213431 - 2²³ = 1400132824823 is a prime.

It is a super-2 number, since 2×1400141213431² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1400141213396 and 1400141213405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1400141213411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18269526 + ... + 18346003.

It is an arithmetic number, because the mean of its divisors is an integer number (350044466800).

Almost surely, 2^{1400141213431} is an apocalyptic number.

1400141213431 is a deficient number, since it is larger than the sum of its proper divisors (36653769).

1400141213431 is an equidigital number, since it uses as much as digits as its factorization.

1400141213431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36653768.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1400141213431 its reverse (1343121410041), we get a palindrome (2743262623472).

The spelling of 1400141213431 in words is "one trillion, four hundred billion, one hundred forty-one million, two hundred thirteen thousand, four hundred thirty-one".