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140019553 is a prime number
BaseRepresentation
bin10000101100010…
…00011101100001
3100202110201201101
420112020131201
5241321111203
621521034401
73320101162
oct1026103541
9322421641
10140019553
1172045843
123aa85a01
132301620b
141484b769
15c45c41d
hex8588761

140019553 has 2 divisors, whose sum is σ = 140019554. Its totient is φ = 140019552.

The previous prime is 140019541. The next prime is 140019563. The reversal of 140019553 is 355910041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78287104 + 61732449 = 8848^2 + 7857^2 .

It is an emirp because it is prime and its reverse (355910041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140019553 - 29 = 140019041 is a prime.

It is not a weakly prime, because it can be changed into another prime (140019563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70009776 + 70009777.

It is an arithmetic number, because the mean of its divisors is an integer number (70009777).

Almost surely, 2140019553 is an apocalyptic number.

It is an amenable number.

140019553 is a deficient number, since it is larger than the sum of its proper divisors (1).

140019553 is an equidigital number, since it uses as much as digits as its factorization.

140019553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2700, while the sum is 28.

The square root of 140019553 is about 11832.9858024085. The cubic root of 140019553 is about 519.2735825925.

Adding to 140019553 its reverse (355910041), we get a palindrome (495929594).

The spelling of 140019553 in words is "one hundred forty million, nineteen thousand, five hundred fifty-three".