Base | Representation |
---|---|
bin | 10100011000000010011… |
… | …111011000110101001111 |
3 | 11221212011102102210202121 |
4 | 110120002133120311033 |
5 | 140420102441333403 |
6 | 2551124333233411 |
7 | 203106201103651 |
oct | 24300237306517 |
9 | 4855142383677 |
10 | 1400201121103 |
11 | 49a905036584 |
12 | 1a7450632867 |
13 | a2066494545 |
14 | 4baad2006d1 |
15 | 26650b3b3bd |
hex | 146027d8d4f |
1400201121103 has 2 divisors, whose sum is σ = 1400201121104. Its totient is φ = 1400201121102.
The previous prime is 1400201121097. The next prime is 1400201121113. The reversal of 1400201121103 is 3011211020041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1400201121103 - 229 = 1399664250191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1400201121113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700100560551 + 700100560552.
It is an arithmetic number, because the mean of its divisors is an integer number (700100560552).
Almost surely, 21400201121103 is an apocalyptic number.
1400201121103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400201121103 is an equidigital number, since it uses as much as digits as its factorization.
1400201121103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1400201121103 its reverse (3011211020041), we get a palindrome (4411412141144).
The spelling of 1400201121103 in words is "one trillion, four hundred billion, two hundred one million, one hundred twenty-one thousand, one hundred three".
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