Base | Representation |
---|---|
bin | 11111110101100101111100… |
… | …101101001001110001101111 |
3 | 200100210000002022012020222121 |
4 | 133311211330231021301233 |
5 | 121323111203140400312 |
6 | 1213445211040053411 |
7 | 41331164434635052 |
oct | 3765457455116157 |
9 | 610700068166877 |
10 | 140022321028207 |
11 | 406851509340a2 |
12 | 13855320004267 |
13 | 6019081c138b7 |
14 | 268118b956a99 |
15 | 112c47ddce707 |
hex | 7f597cb49c6f |
140022321028207 has 2 divisors, whose sum is σ = 140022321028208. Its totient is φ = 140022321028206.
The previous prime is 140022321028201. The next prime is 140022321028243. The reversal of 140022321028207 is 702820123220041.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140022321028207 is a prime.
It is a super-2 number, since 2×1400223210282072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140022321028201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70011160514103 + 70011160514104.
It is an arithmetic number, because the mean of its divisors is an integer number (70011160514104).
Almost surely, 2140022321028207 is an apocalyptic number.
140022321028207 is a deficient number, since it is larger than the sum of its proper divisors (1).
140022321028207 is an equidigital number, since it uses as much as digits as its factorization.
140022321028207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 34.
Adding to 140022321028207 its reverse (702820123220041), we get a palindrome (842842444248248).
The spelling of 140022321028207 in words is "one hundred forty trillion, twenty-two billion, three hundred twenty-one million, twenty-eight thousand, two hundred seven".
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