Base | Representation |
---|---|
bin | 1100101111000010101011… |
… | …1001001101011100001011 |
3 | 1211120121102021021210221220 |
4 | 3023300222321031130023 |
5 | 3313403214113302131 |
6 | 45440323535133123 |
7 | 2643430240631403 |
oct | 313605271153413 |
9 | 54517367253856 |
10 | 14002313025291 |
11 | 4509390732838 |
12 | 16a18aa3741a3 |
13 | 7a7549209976 |
14 | 365a0372b803 |
15 | 194373ee3e96 |
hex | cbc2ae4d70b |
14002313025291 has 4 divisors (see below), whose sum is σ = 18669750700392. Its totient is φ = 9334875350192.
The previous prime is 14002313025289. The next prime is 14002313025301. The reversal of 14002313025291 is 19252031320041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14002313025291 - 21 = 14002313025289 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14002313025691) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2333718837546 + ... + 2333718837551.
It is an arithmetic number, because the mean of its divisors is an integer number (4667437675098).
Almost surely, 214002313025291 is an apocalyptic number.
14002313025291 is a deficient number, since it is larger than the sum of its proper divisors (4667437675101).
14002313025291 is an equidigital number, since it uses as much as digits as its factorization.
14002313025291 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4667437675100.
The product of its (nonzero) digits is 12960, while the sum is 33.
The spelling of 14002313025291 in words is "fourteen trillion, two billion, three hundred thirteen million, twenty-five thousand, two hundred ninety-one".
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