Base | Representation |
---|---|
bin | 11111110101101111000100… |
… | …001111011100011011011111 |
3 | 200100210221100121000011222102 |
4 | 133311233010033130123133 |
5 | 121323241230422300211 |
6 | 1213453510324035315 |
7 | 41331662153314565 |
oct | 3765570417343337 |
9 | 610727317004872 |
10 | 140032111134431 |
11 | 4068931511887a |
12 | 138571b2832b3b |
13 | 6019c82291669 |
14 | 2681839c7da35 |
15 | 112c85362ba3b |
hex | 7f5bc43dc6df |
140032111134431 has 4 divisors (see below), whose sum is σ = 140032158854664. Its totient is φ = 140032063414200.
The previous prime is 140032111134343. The next prime is 140032111134439. The reversal of 140032111134431 is 134431111230041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140032111134431 is a prime.
It is a super-2 number, since 2×1400321111344312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 140032111134394 and 140032111134403.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140032111134439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19148300 + ... + 25430721.
It is an arithmetic number, because the mean of its divisors is an integer number (35008039713666).
Almost surely, 2140032111134431 is an apocalyptic number.
140032111134431 is a deficient number, since it is larger than the sum of its proper divisors (47720233).
140032111134431 is an equidigital number, since it uses as much as digits as its factorization.
140032111134431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47720232.
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 140032111134431 its reverse (134431111230041), we get a palindrome (274463222364472).
The spelling of 140032111134431 in words is "one hundred forty trillion, thirty-two billion, one hundred eleven million, one hundred thirty-four thousand, four hundred thirty-one".
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