14003231421031 has 4 divisors (see below), whose sum is σ = 14003405116272. Its totient is φ = 14003057725792.

The previous prime is 14003231420999. The next prime is 14003231421037. The reversal of 14003231421031 is 13012413230041.

14003231421031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14003231421031 - 2⁵ = 14003231420999 is a prime.

It is a super-2 number, since 2×14003231421031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14003231420987 and 14003231421005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14003231421037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86726635 + ... + 86887948.

It is an arithmetic number, because the mean of its divisors is an integer number (3500851279068).

Almost surely, 2^{14003231421031} is an apocalyptic number.

14003231421031 is a deficient number, since it is larger than the sum of its proper divisors (173695241).

14003231421031 is an equidigital number, since it uses as much as digits as its factorization.

14003231421031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 173695240.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 14003231421031 its reverse (13012413230041), we get a palindrome (27015644651072).

The spelling of 14003231421031 in words is "fourteen trillion, three billion, two hundred thirty-one million, four hundred twenty-one thousand, thirty-one".