Base | Representation |
---|---|
bin | 11111110101101111010101… |
… | …011110001001001100010111 |
3 | 200100210222002201221021001001 |
4 | 133311233111132021030113 |
5 | 121323242323422403341 |
6 | 1213453555131444131 |
7 | 41332002263324662 |
oct | 3765572536111427 |
9 | 610728081837031 |
10 | 140032400200471 |
11 | 40689453304429 |
12 | 138572735b6647 |
13 | 6019cca13175c |
14 | 26818664086d9 |
15 | 112c86dbcad31 |
hex | 7f5bd5789317 |
140032400200471 has 2 divisors, whose sum is σ = 140032400200472. Its totient is φ = 140032400200470.
The previous prime is 140032400200397. The next prime is 140032400200513. The reversal of 140032400200471 is 174002004230041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140032400200471 - 217 = 140032400069399 is a prime.
It is a super-3 number, since 3×1400324002004713 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140032400200171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70016200100235 + 70016200100236.
It is an arithmetic number, because the mean of its divisors is an integer number (70016200100236).
Almost surely, 2140032400200471 is an apocalyptic number.
140032400200471 is a deficient number, since it is larger than the sum of its proper divisors (1).
140032400200471 is an equidigital number, since it uses as much as digits as its factorization.
140032400200471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 28.
The spelling of 140032400200471 in words is "one hundred forty trillion, thirty-two billion, four hundred million, two hundred thousand, four hundred seventy-one".
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